实现数字的逆置问题

public class TestDemoJava1313 {
//形式参数对实际参数进行一份值拷贝

public static void getEveryBitNum(int num){//形式参数
    int bit = 0;
    while(num != 0){
        bit = num%10;
        System.out.print(bit+"  ");
        num/=10;
    }
}
public static int getBit(int number){
    int count=0;
    while(number != 0){
        number/=10;
        count++;
    }
    return count;
}
public static double reverse(int number){//1234  4*10^3+3*10^2+2*10^1+1*10^0

    int bit = getBit(number);//4
    int temp;//余数
    double result=0;
    while(number != 0){
       temp = number%10 ;
       result += temp * Math.pow(10,bit-1);
       bit--;

// result += temp * Math.pow(10,bit-- -1);
// result += temp * Math.pow(10,–bit);
number/=10;
}
return result;
}

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转载自blog.csdn.net/qq_41241541/article/details/89187127