PAT甲1062 Talent and Virtue(25 分)

#include <string.h>
#include <stdio.h>
#include <algorithm>
#include <string>
#include <stack>
#include <math.h>
#include <vector>
#include <iostream>
using namespace std;

int N,L,H;

struct person
{
    int id;
    int virtue;
    int talent;
    int total;
};

vector<person> p[5];

bool cmp(person a,person b)
{
    if(a.total!=b.total)return a.total>b.total;
    else if(a.virtue!=b.virtue)return a.virtue>b.virtue;
    else return a.id<b.id;
}

int main()
{
    int num[5],total=0;
    scanf("%d%d%d",&N,&L,&H);
    for(int i=0;i<N;i++)
    {
        person a;
        scanf("%d%d%d",&a.id,&a.virtue,&a.talent);
        a.total=a.virtue+a.talent;
        if(a.talent>=L&&a.virtue>=L)
        {
            if(a.virtue>=H&&a.talent>=H)
            {
                p[0].push_back(a);
            }
            else if(a.virtue>=H&&a.talent<H)
            {
                p[1].push_back(a);
            }
            else if(a.virtue>=a.talent)
            {
                p[2].push_back(a);
            }
            else
            {
                p[3].push_back(a);
            }
            total++;
        }
    }
    for(int i=0;i<4;i++)
    {
        sort(p[i].begin(),p[i].end(),cmp);
    }
    printf("%d\n",total);
    for(int i=0;i<4;i++)
    {
        for(int j=0;j<p[i].size();j++)
        {
            printf("%08d %d %d\n",p[i][j].id,p[i][j].virtue,p[i][j].talent);
        }
    }
    return 0;
}

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转载自blog.csdn.net/yhy489275918/article/details/82085094