判断完全二叉树、搜索二叉树

完全二叉树
思想:
层次遍历
(1)有右无左,False
(2)左右不全,必须接下来的每一个节点都是叶节点,才是True

import queue
def isCBTtree(head):
    if not head:
        return False
    que=queue.Queue()
    que.put(head)
    flag=False  #激活判断
    while que:
        head=que.get()
        if (not head.left and head.right) or (flag and (head.left or head.right)):
            return False
        if head.left:
            que.put(head.left)
        if head.right:
            que.put(head.right)
        if not head.left or not head.right: #左右不全,阶段开启
            flag=True
    return True

搜索二叉树:
中序遍历的结果是升序

class TreeNode:
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None

class Solution:
    def __init__(self):
        self.res=[]
    def isValidBST(self, root):
        inorder = self.inorder(root)
        return inorder == sorted(set(inorder))

    def inorder(self, root):
        if not root:
            return []
        self.inorder(root.left)
        self.res.append(root.val)
        self.inorder(root.right)
        return self.res

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转载自blog.csdn.net/weixin_40876685/article/details/89068452