MSP430F5529 上手小例程2

MSP430F5529 上手小例程2

  • 按下P2.1,LED1亮1s,快速按下P2.1两次,LED2亮1s

//按下P2.1,LED1亮1s,快速按下P2.1两次,LED2亮1s

#include "msp430f5525.h"

unsigned int n=0;

int main(void)
{
    WDTCTL = WDTPW | WDTHOLD;   // stop watchdog timer

    P1DIR |= BIT0;
    P4DIR |= BIT7;
    P2DIR &= ~BIT1;
    P2REN |= BIT1;
    P2OUT |= BIT1;
    P1OUT &= ~BIT0;
    P4OUT &= ~BIT7;

    P2IE |= BIT1;
    P2IES |= BIT1;
    P2IFG &= ~BIT1;
    _EINT();

    while(1)
    {
        if(n==0)
        {
            P1OUT &= ~BIT0;
            P4OUT &= ~BIT7;
        }
        else if(n==1)
        {
            P1OUT |= BIT0;
            P4OUT &= ~BIT7;
            __delay_cycles(1000000);
            n=0;
        }
        else if(n==2)
        {
            P1OUT &= ~BIT0;
            P4OUT |= BIT7;
            __delay_cycles(1000000);
            n=0;
        }
    }
    return 0;
}

#pragma vector = PORT2_VECTOR
__interrupt void Port2()
{
    unsigned int i=0;
    if(!(P2IN & BIT1))
    {
        __delay_cycles(5000);      //消抖
        if(!(P2IN & BIT1))
        {
            //__delay_cycles(5000);       //如果还是处于按下的状态,即视作未松手,第一次按下
            while(!(P2IN & BIT1)){}           //第一次松手
            n = 1;
            P2IFG &= ~BIT1;
            //__delay_cycles(50000);         //500ms后如果有按键按下,视作第二次按下
            while((P2IN & BIT1))            //500ms-1000ms内如果不按下,视为只按一次
            {
                i++;
                __delay_cycles(1000);
                if(i>1000)
                    return;
             }                              //程序因按下按键在此处跳出
             if(!(P2IN & BIT1))
             {
                 __delay_cycles(5000);       //消抖
                 if(!(P2IN & BIT1))
                 {
                     while(!(P2IN & BIT1)){}           //第二次松手
                     n = 2;
                     P2IFG &= ~BIT1;
                 }
             }
        }
    }
}
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转载自blog.csdn.net/BerryNard/article/details/97634827