线性查找
/**
* 线性查找所有结果
* @param arr
* @param key
* @return
*/
private static List<Integer> seqSearchAll(int[] arr, int key) {
List<Integer> idxs = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
if (arr[i] == key) {
idxs.add(i);
}
}
return idxs;
}
/**
* 线性查找一个结果
* @param arr
* @param key
* @return
*/
private static int seqSearch(int[] arr, int key) {
for (int i = 0; i < arr.length; i++) {
if (arr[i] == key) {
return i;
}
}
return -1;
}
二分查找
/**
* 二分查找所有结果
* @param arr
* @param low
* @param high
* @param key
* @return
*/
private static List<Integer> binarySearchAll(int[] arr, int low, int high, int key) {
if (low > high) {
return new ArrayList<Integer>();
}
int mid = (low + high) / 2;
if (key < arr[mid]) {
return binarySearchAll(arr, low, mid - 1, key);
}
if (key > arr[mid]) {
return binarySearchAll(arr, mid + 1, high, key);
}
List<Integer> results = new ArrayList<Integer>();
int temp = mid - 1;
while (temp >= 0 && arr[temp] == key) {
results.add(temp--);
}
results.add(mid);
temp = mid + 1;
while (temp <= arr.length - 1 && arr[temp] == key) {
results.add(temp++);
}
return results;
}
/**
* 二分查找单个结果
* @param arr
* @param low
* @param high
* @param key
* @return
*/
private static int binarySearch(int[] arr, int low, int high, int key) {
if (low > high) {
return -1;
}
int mid = (low + high) / 2;
if (key > arr[mid]) {
return binarySearch(arr, mid + 1, high, key);
} else if (key < arr[mid]) {
return binarySearch(arr, low, mid - 1, key);
} else {
return mid;
}
}
private static int binarySearch(int[] arr, int key) {
int low = 0;
int high = arr.length - 1;
while (low <= high) {
int mid = (low + high) / 2;
if (key == arr[mid]) {
return mid;
}
if (key < arr[mid]) {
high = mid - 1;
}
if (key > arr[mid]) {
low = mid + 1;
}
}
return -1;
}
插值查找
- 对于数据量较大,关键字分布比较均匀的查找表来说,采用插值查找, 速度较快
- 关键字分布不均匀的情况下,该方法不一定比折半查找要好
/**
* 插值查找所有结果
* @param arr
* @param low
* @param high
* @param key
* @return
*/
private static List<Integer> insertValueSearchAll(int[] arr, int low, int high, int key) {
if (low > high || key < arr[0] || key > arr[arr.length - 1]) {
return new ArrayList<Integer>();
}
int mid = low + (high - low) * (key - arr[low]) / (arr[high] - arr[low]);
if (key < arr[mid]) {
return insertValueSearchAll(arr, low, mid - 1, key);
}
if (key > arr[mid]) {
return insertValueSearchAll(arr, mid + 1, high, key);
}
List<Integer> results = new ArrayList<Integer>();
results.add(mid);
int temp = mid - 1;
while (temp >= 0 && arr[temp] == key) {
results.add(temp--);
}
temp = mid + 1;
while (temp <= arr.length - 1 && arr[temp] == key) {
results.add(temp++);
}
return results;
}
/**
* 插值查找单一结果
* @param arr
* @param low
* @param high
* @param key
* @return
*/
private static int insertValueSearch(int[] arr, int low, int high, int key) {
if (low > high || key < arr[0] || key > arr[arr.length - 1]) {
return -1;
}
int mid = low + (high - low) * (key - arr[low]) / (arr[high] - arr[low]);
if (key < arr[mid]) {
return insertValueSearch(arr, low, mid - 1, key);
}
if (key > arr[mid]) {
return insertValueSearch(arr, mid + 1, high, key);
}
return mid;
}
斐波那契查找
由斐波那契数列 F[k]=F[k-1]+F[k-2] 的性质,可以得到
(F[k]-1)=(F[k-1]-1)+(F[k-2]-1)+1
。该式说明:只要顺序表的长度为F[k]-1,则可以将该表分成长度为F[k-1]-1和F[k-2]-1的两段,即如上图所示。从而中间位置为mid=low+F(k-1)-1
/**
* 斐波那契查找
* @param arr
* @param key
* @return
*/
private static int fibnacciSearch(int[] arr, int key) {
int low = 0;
int high = arr.length - 1;
int k = 1;
while (high > fibonacci(k) - 1) {
k++;
}
int[] temp = Arrays.copyOf(arr, fibonacci(k));
for (int i = high + 1; i < temp.length; i++) {
temp[i] = arr[high];
}
while (low <= high) {
int mid = low + fibonacci(k - 1) - 1;
if (key < temp[mid]) {
high = mid - 1;
k--;
} else if (key > temp[mid]) {
low = mid + 1;
k -= 2;
} else {
return mid <= high ? mid : high;
}
}
return -1;
}
/**
* 获取第k个fibonacci数
* @param k
* @return
*/
private static int fibonacci(int k) {
if (k <= 0) {
throw new IndexOutOfBoundsException();
}
if (k == 1 || k == 2) {
return 1;
}
return fibonacci(k - 1) + fibonacci(k - 2);
}