【C++ 程序】井字棋游戏（人 VS 人）

本来有一个现成的程序，只不过是老版 C++/C 的，复制进 Visual Studio 2019 会报错：
error
然后修改了仍然不太好用，于是决定自己写一个，耗时1.5小时。

图形界面（鼠标控制）见我的博客：
【C++ 程序】井字棋游戏（人 VS 人）（EasyX 图形界面）

人机版链接见文末 See also。

以下是程序：（分析见程序下面）：

程序

//This program is a simple tic-tac-toe game.

#include <iostream>
#include <string>
#include <cstddef>
#include <stdexcept>
using namespace std;

char point_now[3][3] = {
    
     ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ' };
char player = 'X';
unsigned step_count = 0;

int win_lose(char point[3][3], int n)
{
    
    
	if (point[0][0] == point[0][1] && point[0][1] == point[0][2] && point[0][0] == 'X') return 1; // X wins
	if (point[1][0] == point[1][1] && point[1][1] == point[1][2] && point[1][0] == 'X') return 1; // X wins
	if (point[2][0] == point[2][1] && point[2][1] == point[2][2] && point[2][0] == 'X') return 1; // X wins
	if (point[0][0] == point[1][0] && point[1][0] == point[2][0] && point[0][0] == 'X') return 1; // X wins
	if (point[0][1] == point[1][1] && point[1][1] == point[2][1] && point[0][1] == 'X') return 1; // X wins
	if (point[0][2] == point[1][2] && point[1][2] == point[2][2] && point[0][2] == 'X') return 1; // X wins
	if (point[0][0] == point[1][1] && point[1][1] == point[2][2] && point[1][1] == 'X') return 1; // X wins
	if (point[0][2] == point[1][1] && point[1][1] == point[2][0] && point[1][1] == 'X') return 1; // X wins

	if (point[0][0] == point[0][1] && point[0][1] == point[0][2] && point[0][0] == '0') return 2; // 0 wins
	if (point[1][0] == point[1][1] && point[1][1] == point[1][2] && point[1][0] == '0') return 2; // 0 wins
	if (point[2][0] == point[2][1] && point[2][1] == point[2][2] && point[2][0] == '0') return 2; // 0 wins
	if (point[0][0] == point[1][0] && point[1][0] == point[2][0] && point[0][0] == '0') return 2; // 0 wins
	if (point[0][1] == point[1][1] && point[1][1] == point[2][1] && point[0][1] == '0') return 2; // 0 wins
	if (point[0][2] == point[1][2] && point[1][2] == point[2][2] && point[0][2] == '0') return 2; // 0 wins
	if (point[0][0] == point[1][1] && point[1][1] == point[2][2] && point[1][1] == '0') return 2; // 0 wins
	if (point[0][2] == point[1][1] && point[1][1] == point[2][0] && point[1][1] == '0') return 2; // 0 wins

	if (n == 9) return 3; // end up in a draw
	else return 0; // unfinished
}

void game_player_change(char &player)
{
    
    
	if (player == 'X')
		player = '0'; // X -> 0
	else player = 'X';// 0 -> X
}

int main()
{
    
    
	std::cout << "This program is a simple tic-tac-toe game.\nProgrammer:Teddy van Jerry\n" << endl;
	// Print an empty board.
	std::cout << "| |1|2|3|" << endl;
	std::cout << "|A| | | |" << endl;
	std::cout << "|B| | | |" << endl;
	std::cout << "|C| | | |\n" << endl;

	while (win_lose(point_now, step_count) == 0)
	{
    
    
		string location;
		unsigned location_letter = 0; // A/B/C
		unsigned location_number = 0; // 1/2/3

	begin: // a label

		std::cout << "Player " << player << ", make your move: ";
		cin >> location; // input the location (e.g. B2)
		std::cout << endl;

		switch (location[0])
		{
    
    
		case 'a': case 'A':
			location_letter = 0;
			break;
		case 'b': case 'B':
			location_letter = 1;
			break;
		case 'c': case 'C':
			location_letter = 2;
			break;
		default: // illegal input
			location_letter = 100; // indicate an error
			break;
		}

		switch (location[1])
		{
    
    
		case '1':
			location_number = 0;
			break;
		case '2':
			location_number = 1;
			break;
		case '3':
			location_number = 2;
			break;
		default: // illegal input
			location_number = 100; // indicate an error
			break;
		}

		try
		{
    
    
			if (location_letter != 100 && location_number != 100 && point_now[location_letter][location_number] == ' ')
				point_now[location_letter][location_number] = player;
			else throw runtime_error("Illegal input!");
		}
		catch(runtime_error err)
		{
    
    
			std::cout << err.what() << "\nTry Again? Rnter Y or N." << endl;
			char decision;
			cin >> decision;
			if (!cin || decision == 'n' || decision == 'N')
				break;
			else
			{
    
    
				cout << endl;
				goto begin; // go back to the label 'begin'
			}
		}

		// Print the board
		std::cout << "| |1|2|3|" << endl;
		std::cout << "|A|" << point_now[0][0] << "|" << point_now[0][1] << "|" << point_now[0][2] << "|" << endl;
		std::cout << "|B|" << point_now[1][0] << "|" << point_now[1][1] << "|" << point_now[1][2] << "|" << endl;
		std::cout << "|C|" << point_now[2][0] << "|" << point_now[2][1] << "|" << point_now[2][2] << "|" << endl;

		game_player_change(player); // change the player
		++step_count; // count one more time
		std::cout << endl;
	}

	int final_result = win_lose(point_now, step_count);
	switch (final_result)
	{
    
    
	case 1:
		std::cout << "Congratulations! The winner is X." << endl;
		break;
	case 2:
		std::cout << "Congratulations! The winner is 0." << endl;
		break;
	case 3:
		std::cout << "The game ended in a draw." << endl;
		break;
	}
	std::cout << "\nALL RIGHTS RESERVED (c) 2020 Teddy van Jerry" << endl;
	return 0;
}

//Copyright :2020 Teddy van Jerry

输出示例

Output

分析

该程序的优点：
97-115行对于不合法输入进行了判别（分为两种：1.坐标超出范围，2.输入到原来已有棋子的位置上）
编写该程序的思路：
首先写main，如果遇到复杂的内容，另建函数，比如此处的判断输赢和交换选手。
调试过程比较顺利，发现了几个问题。1.棋盘输出位置不对，调整输出棋盘的代码即可。 2.有一种胜利情况没有判别出来，检查发现18，19，20，27，28，29行有坐标写错了（要细致啊！！！）。
感想
能自己写出来这样的程序，真的很有成就感的！！！

【C++ 程序】 井字棋游戏（人 VS 人）

程序

输出示例

分析

See also

猜你喜欢

【C++ 程序】井字棋游戏（人 VS 人）