E1. Median on Segments (Permutations Edition)[如何判断无序中位数] - 代码天地

E1. Median on Segments (Permutations Edition)[如何判断无序中位数]

其他 2018-07-15 16:13:50 阅读次数: 0

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转载自blog.csdn.net/haipai1998/article/details/80985281

E1. Median on Segments (Permutations Edition)[如何判断无序中位数]

E1. Median on Segments (Permutations Edition)

Codeforces Round #496 (Div. 3 ) E1. Median on Segments (Permutations Edition)（中位数计数）

Codeforces Round #496 E1. Median on Segments (Permutations Edition)(思路)

1005E1 Median on Segments (Permutations Edition) 【思维+无序数组求中位数】

Median on Segments (Permutations Edition)

CF1005E1 Median on Segments (Permutations Edition) 思维

Codeforces1005 E1 - Median on Segments (Permutations Edition)

CodeForces - 1005E1 Median on Segments (Permutations Edition)

Codeforces1005E1 - Median on Segments (Permutations Edition)（中位数计数）

Codeforces 1005E1&2 Median on Segments (General Case & Permutations Edition)

CodeForces 1005 E1.Median on Segments (Permutations Edition) (思维->差值)

E1. Median on Segments（找一个数在多少个连续子序列中是中位数）

Codeforces Round #496 (Div. 3) E2. Median on Segments (General Case Edition) 中位数为m的区间的个数

Codeforces Round #496 (Div. 3) E2 - Median on Segments (General Case Edition)

E2. Median on Segments (General Case Edition)【思维】好题

Codeforces Round #496 (Div. 3) E2. Median on Segments (General Case Edition)

codeforcesE2. Median on Segments (General Case Edition)

Codeforces Round #496 (Div. 3) E2 - Median on Segments (General Case Edition)（思维+用bit 位求前缀合）

E1. Array and Segments (Easy version)（暴力） && E2. Array and Segments (Hard version)（线段树维护）

Codeforces Round #535 (Div. 3) E1. Array and Segments (Easy version)(思维+暴力)

cf 1015 E1. Stars Drawing (Easy Edition)

中位数（Median）

E. Intersection of Permutations

E. Median String

Codeforces 981 E - Addition on Segments

L1 Median

Median of Two Sorted Arrays（求中位数）

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1037B--Reach Median(中位数)

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