Java 语言程序设计(第十版) 第十三章 第2题

13.2

编写一下方法,对 ArrayList 里面保存的数字进行排序
public static void shuffle(ArrayList《Number》 list)
//由于用<>显示不出来里面的单词,就用中文的《》代替了

import java.util.ArrayList;
import java.util.Random;

import javax.swing.text.html.HTMLDocument.Iterator;

class ShuffleSortNumber {
    ArrayList<Number> list = new ArrayList<Number>();

    public ShuffleSortNumber() {}
    public ShuffleSortNumber(ArrayList<Number> list) {
        this.list = list;
    }
    public static void shuffle(ArrayList<Number> list) {
        if (list.size() == 0 || list == null) {
            return;
        }
        Random random = new Random();
        for (int i=0; i<list.size(); i++) {
            int index = random.nextInt(list.size());
            Number number = list.get(i);
            list.set(i, list.get(index));
            list.set(index, number);
        }
    }
}

测试:


public class Test13_2 { 
    public static void main(String[] args) {
        ShuffleSortNumber s = new ShuffleSortNumber();
        s.list.add(199);
        s.list.add(89);
        s.list.add(90);
        s.list.add(1299);
        s.list.add(829);
        s.list.add(920);
        s.list.add(2);
        s.list.sort(null);
//      s.shuffle(s.list);
        ShuffleSortNumber.shuffle(s.list);
        for (Number tem: s.list) {
            System.out.println(tem);
        }
    }
}

结果:

2
199
89
829
920
1299
90

类图

这里写图片描述

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转载自blog.csdn.net/qq_37131037/article/details/80719829
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