一个Struts2简单登录实例，eclipse。
通配符实现两种登录方法
结构
基本配置
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>Struts2</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>Struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>Struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>登录界面
Login.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Login</title>
</head>
<body>
<script>
function LoginIdentity() {
if (document.LoginForm.identity.value == "User") {
document.LoginForm.action = "LoginUser"}
else if (document.LoginForm.identity.value == "Administrator") {
document.LoginForm.action = "LoginAdministrator"}
document.LoginForm.submit();
}
</script>
<form name="LoginForm" method="post">
<table align ="center" >
<tr>
<td align ="right"> Login: <input type= "text" name="account"><BR></td>
<td><select name="identity">
<option value="User">User</option>
<option value="Administrator">Administrator</option></select></td>
</tr>
<tr>
<td align ="right">Password:<input type= "password" name="passWord"><BR></td>
<td><input type= "button" value="OK" onclick="LoginIdentity()"></td>
</tr>
</table>
</form>
</body>
</html>
struts.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.5//EN"
"http://struts.apache.org/dtds/struts-2.5.dtd">
<struts>
<constant name="struts.devMode" value="true" />
<constant name="struts.enable.DynamicMethodInvocation" value="false" />
<!-- 使用！方法时需要开启DMI功能 -->
<!-- <constant name="struts.enable.DynamicMethodInvocation" value="true" /> -->
<package name="struts2" extends="struts-default">
<!-- Struts2.5特有问题，得允许内部访问。这个是全局的，可以单独写在action里
但是如果写在action里的话就不能继承ActionSupport类了，并不明白。。。 -->
<global-allowed-methods>regex:.*</global-allowed-methods>
<action name="Login*" class="com.struts2.LoginAction" method="{1}">
<!-- 这个{1}代表的是前面的name属性中的第一个* -->
<result name="usersuccess">/UserWelcome.jsp</result>
<result name="adminsuccess">/AdministratorWelcome.jsp</result>
<result name="failed">/ERRORR.jsp</result>
</action>
</package>
</struts>Action的文件
LoginAction.java
package com.struts2;
import com.opensymphony.xwork2.ActionSupport;
public class LoginAction extends ActionSupport{
private String account;
private String passWord;
/* private String identify;*/
public String getPassWord() {
return passWord;
}
public void setPassWord(String passWord) {
this.passWord = passWord;
}
public void setAccount(String account) {
this.account = account;
}
public String getAccount() {
return account;
}
/* public void setIdentify(String identify) {
this.identify = identify;
}
public String getIdentify() {
return identify;
}*/
public String Administrator() {
if (getPassWord().equals(getAccount())) {
return "adminsuccess";}
else {
return "failed";}
}
public String User() {
if (getPassWord().equals(getAccount())) {
return "usersuccess";}
else {
return "failed";}
}
}然后瞎写成功界面/失败界面就行。记得在struts.xml里配置，OJBK。