MySQL数据库的使用方法(连表查询、分页查询)

数据库连表查询

学生表student

老师表teacher

课程表course

选课表student_course

按“0001”号课程成绩由高到低顺序显示所有学生学号、姓名、成绩(二表连接);

SELECT
       student.student_id,
       student.student_name,
       student_course.score
FROM
       student,
       student_course
WHERE
       student.student_id = student_course.student_id
AND student_course.course_id = '0001'
ORDER BY
       student_course.score DESC; #DESC代表降序排列;ASC代表升序排列

当两个(多个)表中有相同的字段(属性,列名)时,使用表名(或表别名).列名的形式对查询内容和条件内容进行区分。

运行结果:

2 按“高等数学”课程成绩由高到低顺序显示所有学生姓名、学号、分数、课程名(三表连接);

SELECT
       st.student_id,
       st.student_name,
       sc.score,
       co.course_name
FROM
       student AS st,
       student_course AS sc,
       course AS co
WHERE
       st.student_id = sc.student_id
AND sc.course_id = co.course_id
AND co.course_name = '高等数学'
ORDER BY
       sc.score DESC; #DESC代表降序排列;ASC代表升序排列

运行结果:

查询有薪水差额的任意两位教师(单表连接查询);

SELECT
       t1.teacher_id AS '教工号1',
       t1.teacher_name AS '教师姓名1',
       t2.teacher_id AS '教工号2',
       t2.teacher_name AS '教师姓名2'
FROM
       teacher t1,
       teacher t2
WHERE
       t1.teacher_salary > t2.teacher_salary;

运行结果:

查询既学过“0001”又学过“0002”号课程的所有学生学号;

SELECT
	sc1.student_id '学号'
FROM
	student_course sc1,
	student_course sc2
WHERE
	sc1.student_id = sc2.student_id
AND sc1.course_id = '0001'
AND sc2.course_id = '0002';

运行结果:

查询“0001”号课程比“0002”号课程成绩低的所有学生学号姓名;

SELECT
	st.student_id '学号',
	st.student_name '姓名'
FROM
	student_course sc1,
	student_course sc2,
	student st
WHERE
	sc1.student_id = sc2.student_id
AND sc1.student_id = st.student_id
AND sc1.course_id = '0001'
AND sc2.course_id = '0002'
AND sc1.score < sc2.score;

运行结果:

6. 查询“0003”老师教的所有的学生

SELECT
	st.*
FROM
        student as st inner join teacher as th on st.teacher_id=th.teacher_id where th.teacher_id =0003

mysql数据库分页查询

select * from student limit 2,3

运行结果

 上面查询中的2代表从第2条数据之后开始,注意是第2条数据之后,不包含第2条数据。3代表总共查询3条记录。那么limit 2,3代表从第2(不包含第2数据开始查询出3条记录。

创建表及插入数据

我们按照以下的语句对我们的数据库操进行建表和插入数据,方便接下来对我们的两张表进行操作和演示

#数据库建表
CREATE TABLE IF NOT EXISTS 'student' (
    'id' INT AUTO_INCREMENT,
    'name' VARCHAR(18) NOT NULL COMMENT '姓名',
    'age' VARCHAR(18) NOT NULL COMMENT '年龄',
    'weight' VARCHAR(18) NOT NULL COMMENT '体重',
    'sex' VARCHAR(18) NOT NULL COMMENT '性别',
    'height' VARCHAR(18) NOT NULL COMMENT '身高',
    'teacher_id' INT NOT NULL COMMENT '教师id',
    'create_time' datetime NOT NULL DEFAULT CURRENT_TIMESTAMP COMMENT '创建时间',
    PRIMARY KEY ('id')
) ENGINE = InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE IF NOT EXISTS 'teacher'(
    'id' INT AUTO_INCREMENT,
    'name' VARCHAR(18) NOT NULL COMMENT '姓名',
    'age'  VARCHAR(18) NOT NULL COMMENT '年龄',
    'weight'  VARCHAR(18) NOT NULL COMMENT '体重',
    'height' VARCHAR(18) NOT NULL COMMENT '身高',
    'sex'  VARCHAR(18) NOT NULL COMMENT '性别',
    'create_time' datetime NOT NULL DEFAULT CURRENT_TIMESTAMP COMMENT '创建时间',
    PRIMARY KEY ('id')
)ENGINE = InnoDB DEFAULT CHARSET=utf8;
# 在学生表中插入数据
INSERT INTO student(name,age,weight,sex,height,teacher_id)VALUES
                    ("花花","18","50","女","165",1),
                    ("菲菲","17","47","男","162",1),
                    ("西西","19","45","女","161",2),
                    ("玥玥","16","40","女","160",1),
                    ("涵涵","15","49","男","164",2),
                    ("涵涵","17","48","男","163",2),
                    ("若若","20","45","女","161",1);
# 在老师表中插入数据
INSERT INTO teacher (name,age,weight,height,sex)VALUES
                    ("高飞","26","64","170","女"),
                    ("张宇","28","74","179","男");

查看学生表有无数据

查看老师表有无数据

删除表

更新表

排序

这里时间是一样的,因为我是批量插入的所以没有变化

分组

这里的涵涵原本是有两个的现在只有一个了

如果执行上面这句报错进入/etc目录下,在my.cnf中加上下面图片所示的代码

连表查询

 

查询多少个女学生

 

查询男生的总体重

增加一个老师表中的字段,用于统计有多少学生

更新老师表中的数据

 

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转载自blog.csdn.net/ALLENsakaru/article/details/85147372