【oauth2.0】【2】JAVA 客户端模式

含义:用户直接向客户端注册,客户端以自己的名义要求"服务提供商"提供服务,其实不存在授权问题

步骤:

(A)客户端向认证服务器进行身份认证,并要求一个访问令牌(token)。

(B)认证服务器确认无误后,向客户端提供访问令牌。

(C)用令牌请求资源服务器的资源

摘要:

1,JAVA代码中访问

2,Postman中访问

3,Swagger中访问

正文:

1,JAVA代码中访问

我的环境是Spring Boot,实现代码:

pom.xml

<dependency>
    <groupId>org.apache.oltu.oauth2</groupId>
    <artifactId>org.apache.oltu.oauth2.client</artifactId>
    <version>0.31</version>
</dependency>

OAuthClientUtil.java

public class OAuthClientUtil {
    private static Logger logger = LoggerFactory.getLogger(OAuthClientUtil.class.getName());

    //Config.ACCESS_TOKEN_URL 认证服务器获取token的地址;Config.OAUTH_USERNAME 账号;Config.OAUTH_PASSWORD:密码
    public static String getApiToken()throws OAuthProblemException{
        logger.info("api getApiToken");
        String accessToken = null;
        OAuthClient oAuthClient = new OAuthClient(new URLConnectionClient());
        try {
            OAuthClientRequest request = OAuthClientRequest
                    .tokenLocation(Config.ACCESS_TOKEN_URL)
                    .setGrantType(GrantType.CLIENT_CREDENTIALS)
                    .setUsername(Config.OAUTH_USERNAME)
                    .setPassword(Config.OAUTH_PASSWORD)
                    .buildQueryMessage();

            request.addHeader("Accept", "application/json");
            request.addHeader("Content-Type", "application/json");
            String auth = Base64Util.encode(Config.OAUTH_USERNAME + ':' + Config.OAUTH_PASSWORD);
            request.addHeader("Authorization", "Basic " + auth);

            OAuthAccessTokenResponse oAuthResponse = oAuthClient.accessToken(request, OAuth.HttpMethod.POST); //去服务端请求access_token,并返回响应
            accessToken = oAuthResponse.getAccessToken(); //获取服务端返回过来的access_token
            logger.info("api token: " + accessToken);
        } catch (OAuthSystemException e) {
            e.printStackTrace();
        }

        return accessToken;
    }

}

Base64Util.java

public class Base64Util {
        //编码
        public static String encode(String s) {
            if (s == null)
                return null;
            String res = "";
            try {
                res = new sun.misc.BASE64Encoder().encode(s.getBytes("GBK"));
            } catch (UnsupportedEncodingException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return res;
        }

        //解码
        public static String decode(String s) {
            if (s == null)
                return null;
            BASE64Decoder decoder = new BASE64Decoder();
            try {
                byte[] b = decoder.decodeBuffer(s);
                return new String(b,"GBK");
            } catch (Exception e) {
                return null;
            }
        }
}

使用授权访问接口

public String scanTrainQrode(String param) {
    String respContent = ""; //返回的内容
    String apiToken = null;
    try {
        apiToken = OAuthClientUtil.getApiToken(); //获取token
        String requestUrl = String.format(Config.URL, param, apiToken); //拼接接口地址(例:https://cn.bing.com?param=param&api_token=apiToken)
        String result = HttpHelper.SendPOST(requestUrl); //访问接口地址

        if (StringUtils.isNotBlank(result)) { //解析返回的结果
            JSONObject jsonObject = JSONObject.fromObject(result);
            if(jsonObject.containsKey("msg")) respContent = jsonObject.getString("msg");
        }
    } catch (OAuthProblemException e) {
        e.printStackTrace();
    }
    return respContent;
}

2,Postman中访问

Postman为模拟网络请求的工具,见参考博客2

-------------------------------------------

3,Swagger中访问

value中填写bearer + 空格 + token(例:bearer 49305daf-e566-4f9d-8f83-e74af5ae47e1)

参考博客:

1,Java的oauth2.0 服务端与客户端的实现 - jing12062011的博客 - CSDN博客
https://blog.csdn.net/jing12062011/article/details/78147306

2,Oauth2授权模式访问之客户端模式(client_credentials)访问 - 面朝大海,春暖花开 - CSDN博客

https://blog.csdn.net/u013887008/article/details/80574905

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转载自www.cnblogs.com/huashengweilong/p/10690169.html