蓝桥杯官网练习题（凑算式）

类似填空题：

①算式900：

https://blog.csdn.net/s44Sc21/article/details/132746513?spm=1001.2014.3001.5501https://blog.csdn.net/s44Sc21/article/details/132746513?spm=1001.2014.3001.5501

②九宫幻方③七星填数④幻方填空：
https://blog.csdn.net/s44Sc21/article/details/132429826?spm=1001.2014.3001.5501https://blog.csdn.net/s44Sc21/article/details/132429826?spm=1001.2014.3001.5501

⑤纸牌三角形：

https://blog.csdn.net/s44Sc21/article/details/132784482?csdn_share_tail=%7B%22type%22%3A%22blog%22%2C%22rType%22%3A%22article%22%2C%22rId%22%3A%22132784482%22%2C%22source%22%3A%22s44Sc21%22%7Dhttps://blog.csdn.net/s44Sc21/article/details/132784482?csdn_share_tail=%7B%22type%22%3A%22blog%22%2C%22rType%22%3A%22article%22%2C%22rId%22%3A%22132784482%22%2C%22source%22%3A%22s44Sc21%22%7D

⑥搭积木：

https://blog.csdn.net/s44Sc21/article/details/132840321?csdn_share_tail=%7B%22type%22%3A%22blog%22%2C%22rType%22%3A%22article%22%2C%22rId%22%3A%22132840321%22%2C%22source%22%3A%22s44Sc21%22%7Dhttps://blog.csdn.net/s44Sc21/article/details/132840321?csdn_share_tail=%7B%22type%22%3A%22blog%22%2C%22rType%22%3A%22article%22%2C%22rId%22%3A%22132840321%22%2C%22source%22%3A%22s44Sc21%22%7D⑦五星填数：

https://blog.csdn.net/s44Sc21/article/details/132839777?spm=1001.2014.3001.5502https://blog.csdn.net/s44Sc21/article/details/132839777?spm=1001.2014.3001.5502

题目描述

本题为填空题，只需要算出结果后，在代码中使用输出语句将所填结果输出即可。

     B      DEF
A + --- + ------- = 10
     C      GHI

这个算式中 A ~ I 代表 0 ~ 9 的数字，不同的字母代表不同的数字。

比如： 6+8/3+952/714 就是一种解法，5+3/1+972/486 是另一种解法。

这个算式一共有多少种解法？

运行限制

• 最大运行时间：1s
• 最大运行内存: 128M

import java.util.Scanner;
// 1:无需package
// 2: 类名必须Main, 不可修改

public class Main {
  static int[] a=new int[9];
  static int[] biaoji=new int[10];
  static int ans=0;
  static int flag=0;
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        //在此输入您的代码...
        scan.close();
        dfs(0);
        System.out.println(ans);
    }
    public static void dfs(int n){
      if(n==9){
        int A=a[0];
        int B=a[1];
        int C=a[2];
        int D=a[3]*100+a[4]*10+a[5];
        int E=a[6]*100+a[7]*10+a[8];
        if((A+B*1.0/+C+D*1.0/E)==10){
          ans++;
          return;
        }
        else{
          return;
        }
      }
      if(a[n]!=0){
        dfs(n+1);
      }
      for(int i=1;i<=9;i++){
        if(biaoji[i]==0&&a[n]==0){
          biaoji[i]=1;
          a[n]=i;
          dfs(n+1);
          biaoji[i]=0;
          a[n]=0;
        }
      }
    }
}