1065 A+B and C (64bit) (20 分)
Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
心得:要先求出res,在判断是否越界(有点坑)。
#include<iostream>
#include<cstdio>
#include<cstdlib>
using namespace std;
typedef long long LL;
int main(void)
{
LL a,b,c,res;
int t,i;
scanf("%d",&t);
for(i=1;i<=t;i++)
{
scanf("%lld %lld %lld",&a,&b,&c);
res=a+b;
printf("Case #%d: ",i);
if(a>0&&b>0&&res<0)
{
printf("true\n");
}
else if(a<0&&b<0&&res>=0)
{
printf("false\n");
}
else if(res>c) printf("true\n");
else printf("false\n");
}
return 0;
}