1060 Are They Equal (25分)

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as $0 with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.$

Input Specification:

Each input file contains one test case which gives three numbers

Output Specification:

For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10^k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding.

Sample Input 1:

3 12300 12358.9

Sample Output 1:

YES 0.123*10^5

Sample Input 2:

3 120 128

Sample Output 2:

NO 0.120*10^3 0.128*10^3

未全过代码

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include <climits>
 3 #include<iostream>
 4 #include<vector>
 5 #include<queue>
 6 #include<map>
 7 #include<set>
 8 #include<stack>
 9 #include<algorithm>
10 #include<string>
11 #include<cmath>
12 using namespace std;
13 
14 int main()
15 {
16     int N;
17     float num1, num2;
18     int p1, p2,n1,n2;
19     p1 = p2 = 0;
20     n1 = n2 = 0;
21     cin >> N >> num1 >> num2;
22     stack<int>S1, S2;
23     while (num1 - floor(num1) != 0.0)
24     {
25         num1 *= 10.0;
26         p1++;
27     }
28     while (num2 - floor(num2) != 0.0)
29     {
30         num2 *= 10.0;
31         p2++;
32     }
33     int N1 = static_cast<int>(num1);
34     int N2 = static_cast<int>(num2);
35     while (N1)
36     {
37         S1.push(N1 % 10);
38         N1 /= 10;
39         n1++;
40     }
41     while (N2)
42     {
43         S2.push(N2 % 10);
44         N2 /= 10;
45         n2++;
46     }
47     n1 -= p1;
48     n2 -= p2;
49     int ans1 = 0, ans2 = 0;
50     int s1 = 0, s2 = 0;
51     for (int i = 0; i < N; i++)
52     {
53         if (!S1.empty()) {
54             ans1 = ans1 * 10 + S1.top();
55             S1.pop();
56             s1++;
57         }
58         if (!S2.empty()) {
59             ans2 = ans2 * 10 + S2.top();
60             S2.pop();
61             s2++;
62         }
63     }
64     if (s1 != N) {
65         ans1 *= 10;
66         s1++;
67     }
68     if (s2 != N) {
69         ans2 *=10;
70         s2++;
71     }
72     if (ans1 == ans2 && n1 == n2)
73     {
74         if(ans1==0)
75             cout << "YES "<< ans1;
76         else
77         {
78             cout << "YES" << " 0." << ans1;
79             if (n1 > 0)
80                 cout << "*10^" << n1;
81         }
82     }
83     else
84     {
85         cout << "NO ";
86         cout << "0." << ans1;
87         if (n1 > 0)
88             cout << "*10^" << n1<<" ";
89         cout << "0." << ans2;
90         if (n2 > 0)
91             cout << "*10^" << n1;
92     }
93 }

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