数码管动态显示0-F代码：
单片机晶振需要调节为11.0592，只有在这个状态下X*110次循环才能约等于X毫秒
下文循环约为1s
#include <reg52.h>
#define uchar unsigned char
void main()
{
uchar code duanxuan[] = {
0x3f,0x06,0x5b,0x4f, //0,1,2,3
0x66,0x6d,0x7d,0x07, //4,5,6,7
0x7f,0x6f,0x77,0x7c, //8,9,A,B
0x39,0x5e,0x79,0x71}; //C,D,E,F 段选
uchar code weixuan[] = {
0x1c,0x18,0x14,0x10, //1,2,3,4
0xc,0x8,0x4,0x0}; //5,6,7 位选
while(1)
{
int i,m,n=0;
for(i=0;i<16;i++)
{
P0 = duanxuan[i];
for(m=0;m<11000;m++)
{
P2 = weixuan[n];
n = (n+1)%8;
}
}
}
}
实验结果：
