汉诺塔演示C语言

参考了一下easyx.cn的代码 并加以修改 逻辑更加清楚

#include<easyx.h>
#define MAX 5
typedef struct MyRect
{
	int left;
	int top;
	int right;
	int bottom;
}MYRECT;

typedef struct MyStack
{
	MYRECT rect[MAX+1];
	int    top;
}MYSTACK;

MYSTACK g_Pillar[3] = { 0 };
int		g_nPan = MAX;
// 函数声明
void Hannoi(int n, char a, char b, char c);		// 汉诺塔递归
void Move  (int n, char a, char b);				// 移动过程
int  switchab(char a);

int main()
{
	initgraph(800, 650);
	setbkcolor(WHITE);
	cleardevice();
	//三根柱子
	setlinecolor(RED);
	line(400, 110, 400, 500);
	line(600, 110, 600, 500);
	line(200, 110, 200, 500);
	//底座
	setfillcolor(LIGHTGRAY);
	fillrectangle(80, 501, 720, 510);
	//-------------
	for (int i = 0; i < MAX; i++)
	{
		g_Pillar[0].top++;
		g_Pillar[0].rect[g_Pillar->top].left   = 115  + i * 5;
		g_Pillar[0].rect[g_Pillar->top].top    = 480  - i * 20;
		g_Pillar[0].rect[g_Pillar->top].right  = 285  - i * 5;
		g_Pillar[0].rect[g_Pillar->top].bottom = 498  - i * 20;
		
		solidrectangle(g_Pillar[0].rect[g_Pillar[0].top].left, g_Pillar[0].rect[g_Pillar[0].top].top,
			g_Pillar[0].rect[g_Pillar[0].top].right, g_Pillar[0].rect[g_Pillar[0].top].bottom);
	}
	Hannoi(g_nPan, 'a', 'b', 'c');

	//-------------
	closegraph();
	return 0;
}

void Hannoi(int n, char a, char b, char c)
{
	if (n == 1)
		Move(1, a, c);
	else
	{
		Hannoi(n - 1, a, c, b);
		Move(n, a, c);
		Hannoi(n - 1, b, a, c);
	}
}
// 移动过程
void Move(int n, char a, char b)
{
	int dx = 0, iSrc = 0, iDst = 0;
	dx   = switchab(b) - switchab(a);						// 目的钢针与源钢针的位置差值
	iSrc = switchab(a);										// 源钢针钢针号
	iDst = switchab(b);										// 目的钢针号

	MYRECT pan1 = { 0 };//移动前的盘子
	MYRECT pan2 = { 0 };//移动后的盘子

	// 源栈与目的栈值的传递
	pan1 = g_Pillar[iSrc].rect[g_Pillar[iSrc].top];
	g_Pillar[iSrc].top--;

	g_Pillar[iDst].top++;				
	pan2.left	= pan1.left + dx * 200;
	pan2.top	= 500 - g_Pillar[iDst].top * 20;
	pan2.right	= pan1.right + dx * 200;
	pan2.bottom = 500 - g_Pillar[iDst].top * 20 + 18;
	g_Pillar[iDst].rect[g_Pillar[iDst].top] = pan2;
	// 向上运动
	while (pan1.top >= 100)
	{
		setfillcolor(GREEN);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);
		Sleep(10);
		setfillcolor(WHITE);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);
		setlinecolor(RED);
		line((pan1.left + pan1.right) / 2, pan1.top, (pan1.left + pan1.right) / 2, pan1.bottom);	// 重新画上被擦掉原有的红线
		pan1.top -= 10;
		pan1.bottom -= 10;
	}

	// 向左或右运动，与 i3 的正负有关
	while (pan1.right != pan2.right)
	{
		setfillcolor(GREEN);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);
		Sleep(10);
		setfillcolor(WHITE);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);
		if (dx < 0)											// i3<0向左移
		{
			pan1.left -= 20;
			pan1.right -= 20;
		}
		else												// i3>0向右移
		{
			pan1.left += 20;
			pan1.right += 20;
		}
	}

	// 向下运动
	while (pan1.bottom <= pan2.bottom)
	{
		setfillcolor(GREEN);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);

		Sleep(10);
		setfillcolor(WHITE);
		solidrectangle(pan1.left, pan1.top, pan1.right, pan1.bottom);
		setlinecolor(RED);
		if (pan1.top > 100)									// 重画被擦掉的红线
		{
			line((pan1.left + pan1.right) / 2, pan1.top, (pan1.left + pan1.right) / 2, pan1.bottom);
		}
		pan1.top += 10;
		pan1.bottom += 10;
	}

	// 在目的钢针上的相应位置绘制出黄色矩形块
	setfillcolor(YELLOW);
	solidrectangle(pan1.left, pan1.top-10, pan1.right, pan1.bottom-10);
}

int switchab(char a)
{
	switch (a)
	{
	case 'a':
		return 0;
	case 'b':
		return 1;
	case 'c':
		return 2;
	}
	return 0;
}