Spark高级编程(一):WordCount 排序

版权声明: https://blog.csdn.net/weixin_39966065/article/details/89713878

目录

 

一:限制条件

二:逻辑思路

三:实战代码


一:限制条件

sortByKey()排序只针对 Tuple2 结构的 key 

二:逻辑思路

(1)使用 mapToPair(transformation算子) 进行key-value 映射反转 
 (2)再次依据 reduceByKey 执行

package cn.spark.study.core;

import java.util.Arrays;

import org.apache.spark.SparkConf;
import org.apache.spark.api.java.JavaPairRDD;
import org.apache.spark.api.java.JavaRDD;
import org.apache.spark.api.java.JavaSparkContext;
import org.apache.spark.api.java.function.FlatMapFunction;
import org.apache.spark.api.java.function.Function2;
import org.apache.spark.api.java.function.PairFunction;
import org.apache.spark.api.java.function.VoidFunction;

import scala.Tuple2;

/**
 * 排序的wordcount程序
 * @author Administrator
 *
 */
public class SortWordCount {

	public static void main(String[] args) {
		// 创建SparkConf和JavaSparkContext
		SparkConf conf = new SparkConf()
				.setAppName("SortWordCount")
				.setMaster("local"); 
		JavaSparkContext sc = new JavaSparkContext(conf);
		
		// 创建lines RDD
		JavaRDD<String> lines = sc.textFile("C://Users//Administrator//Desktop//spark.txt");
		
		// 执行我们之前做过的单词计数
		JavaRDD<String> words = lines.flatMap(new FlatMapFunction<String, String>() {

			private static final long serialVersionUID = 1L;

			@Override
			public Iterable<String> call(String t) throws Exception {
				return Arrays.asList(t.split(" "));  
			}
			
		});
		
		JavaPairRDD<String, Integer> pairs = words.mapToPair(
				
				new PairFunction<String, String, Integer>() {

					private static final long serialVersionUID = 1L;

					@Override
					public Tuple2<String, Integer> call(String t) throws Exception {
						return new Tuple2<String, Integer>(t, 1);
					}
					
				});
		
		JavaPairRDD<String, Integer> wordCounts = pairs.reduceByKey(
				
				new Function2<Integer, Integer, Integer>() {

					private static final long serialVersionUID = 1L;

					@Override
					public Integer call(Integer v1, Integer v2) throws Exception {
						return v1 + v2;
					}
					
				});
		
		// 到这里为止,就得到了每个单词出现的次数
		// 但是,问题是,我们的新需求,是要按照每个单词出现次数的顺序,降序排序
		// wordCounts RDD内的元素是什么?应该是这种格式的吧:(hello, 3) (you, 2)
		// 我们需要将RDD转换成(3, hello) (2, you)的这种格式,才能根据单词出现次数进行排序把!
		
		// 进行key-value的反转映射
		JavaPairRDD<Integer, String> countWords = wordCounts.mapToPair(
				
				new PairFunction<Tuple2<String,Integer>, Integer, String>() {

					private static final long serialVersionUID = 1L;

					@Override
					public Tuple2<Integer, String> call(Tuple2<String, Integer> t)
							throws Exception {
						return new Tuple2<Integer, String>(t._2, t._1);
					}
					
				});
		
		// 按照key进行排序
		JavaPairRDD<Integer, String> sortedCountWords = countWords.sortByKey(false);
		
		// 再次将value-key进行反转映射
		JavaPairRDD<String, Integer> sortedWordCounts = sortedCountWords.mapToPair(
				
				new PairFunction<Tuple2<Integer,String>, String, Integer>() {

					private static final long serialVersionUID = 1L;

					@Override
					public Tuple2<String, Integer> call(Tuple2<Integer, String> t)
							throws Exception {
						return new Tuple2<String, Integer>(t._2, t._1);
					}
					
				});
		
		// 到此为止,我们获得了按照单词出现次数排序后的单词计数
		// 打印出来
		sortedWordCounts.foreach(new VoidFunction<Tuple2<String,Integer>>() {
			
			private static final long serialVersionUID = 1L;

			@Override
			public void call(Tuple2<String, Integer> t) throws Exception {
				System.out.println(t._1 + " appears " + t._2 + " times.");  	
			}
			
		});
		
		// 关闭JavaSparkContext
		sc.close();
	}
	
}

三:实战代码

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转载自blog.csdn.net/weixin_39966065/article/details/89713878
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