Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800×600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤800) and N (≤600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0,224). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:
5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24
Sample Output:
24
代码:
#include "iostream"
#include "string"
#include "map"
using namespace std;
int main(){
int m,n;
map<string,int> mp;
string current;
scanf("%d %d",&m,&n);
for (int i=0; i<n; i++) {
for (int j=0; j<m; j++) {
cin >> current;
if (mp.find(current)!=mp.end()) {
mp[current]++;
}
else{
mp[current]=1;
}
}
}
string k;
int max=0;
map<string,int>::iterator it=mp.begin();
while (it!=mp.end()) {
if (it->second>max) {
k=it->first;
max=it->second;
}
it++;
}
cout << k;
}
反思;
此题很简单,除了map之外,还可以运用擂台pk方法去做,具体和一维数组找dominate number 一样,有异曲同工之处。