剑指 Offer 07. 重建二叉树(递归)

在这里插入图片描述
递归思想 每个点都当做跟结点去中序数组中划分左右子树

    HashMap<Integer,Integer> map = new HashMap<>();
    private TreeNode build(int[] pre ,int l1 ,int r1 ,int l2 ,int r2){
    
    
        if (l1 > r1) return null;
        TreeNode root = new TreeNode(pre[l1]);
        int in_root = map.get(pre[l1]);
        int left = in_root - l2;
        root.left = build(pre,l1+1 ,l1+left, l2,in_root - 1);
        root.right = build(pre,l1+left+1 ,r1 ,in_root+1 ,r2);
        return root;
    }
    public TreeNode buildTree(int[] preorder, int[] inorder) {
    
    
        for (int i = 0; i < inorder.length; i++)
            map.put(inorder[i],i);
        return build(preorder,0,preorder.length-1,0,preorder.length-1);
    }

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转载自blog.csdn.net/qq_43434328/article/details/115100197