快速幂×快速乘

 快速乘的速度并不能加速两个数相乘,但是可以防止数据超过long long 而最大化速度

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define maxn 10
ll quikly1(ll ans,ll i,ll m)///快速乘
{
      ll an1=0;
      while(i)
      {
            if(i&1)
            {
                  an1+=ans;
                  an1%=m;
            }
            ans+=ans;
            ans%=m;
            i>>=1;

      }
      return an1;
}
ll quikly2( ll i ,ll m)///快速幂
{
      ///2的i次方对m取模
      ll ans=1;
      ll x=2;
      while (i ) {
            if(i&1)
            {
                  ans=quikly1(ans,x,m);
            }
            x=quikly1(x,x,m);
            i>>=1;

      }
      return ans;
}
int main()
{
      /// 求2的n次方对m取模
      long long  n , m ;
      while (scanf("%lld%lld",&n,&m)!=EOF) {
            if(n==1)
            {
                  printf("%lld\n",n%m);
                  continue;
            }

            ll ans=1;
            ans=quikly2(n,m);
            //ans-=2;
            //while(ans<0) ans+=m;
            printf("%lld\n",ans);
      }

}

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转载自blog.csdn.net/henu_1710252529/article/details/82048595