排序 pat1055 The World's Richest (25 分) **

一开始用二维数组保存,但是内存占用太大,复杂度太高,过不了所有点

#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;

typedef struct node
{
	int age;
	char name[9];
	int worth;
	
}record;

bool cmp(record a,record b)
{
	if(a.worth != b.worth)
		return a.worth > b.worth;
	else if(a.age != b.age)
		return a.age < b.age;
	else if (strcmp(a.name,b.name) != 0)
		return strcmp(a.name,b.name) < 0;
}
int main()
{
	record s[10000];
	record temp1[10][100];
	int n,k,q[100000];
	scanf("%d %d",&n,&k);
	for(int i =0;i<n;i++)
	{
		scanf("%s %d %d",s[i].name,&s[i].age,&s[i].worth);
//		printf("%s %d %d\n",s[i].name,s[i].age,s[i].worth);
	} 
	
	int out[100],l,r,flag[1000] = {0},temp[1000] = {0};
	
	for(int j = 1;j<=k;j++)
	{
		int sum = 0;
		scanf("%d %d %d",&out[j],&l,&r);
		for(int i =0;i<n;i++)
		{ 
			if(s[i].age <=r && s[i].age >= l)
			{
				flag[j] = 1;
				temp1[j][sum].age = s[i].age;
				temp1[j][sum].worth = s[i].worth;
				strcpy(temp1[j][sum].name,s[i].name);
				sum++;
			}
				
		}
			temp[j] = sum ;
			sort(temp1[j],temp1[j]+sum,cmp);
	}
	
	for(int i = 1;i<=k;i++)
	{
		printf("Case #%d:\n",i);
		if(flag[i] == 1)
		{
			for(int j = 0;j<out[i] && j<temp[i];j++ )
			{
					printf("%s %d %d\n",temp1[i][j].name,temp1[i][j].age,temp1[i][j].worth);
			}
			
		}
		else
			printf("None\n");
	}
	
	
	return 0;
} 
在这里插入代码片

emmmm
看了算法笔记,好像根本没有必要来设置二维数组
直接排序,根据年龄要求从前往后输出。
设置一个P来记录有多少符合的,为0就输出none

#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;

typedef struct node
{
	int age;
	char name[9];
	int worth;
	
}record;

bool cmp(record a,record b)
{
	if(a.worth != b.worth)
		return a.worth > b.worth;
	else if(a.age != b.age)
		return a.age < b.age;
	else if (strcmp(a.name,b.name) != 0)
		return strcmp(a.name,b.name) < 0;
}
int main()
{
	record s[100010],sum[100010];
	int age[100010] = {0};
	int n,k;
	scanf("%d %d",&n,&k);
	for(int i =0;i<n;i++)
	{
		scanf("%s %d %d",s[i].name,&s[i].age,&s[i].worth);
//		printf("%s %d %d\n",s[i].name,s[i].age,s[i].worth);
	} 
	sort(s,s+n,cmp);
	int index = 0;
	for(int i =0;i<n;i++)
	{
		
		if(age[s[i].age] < 100)
		{
			age[s[i].age]++;
			sum[index] = s[i];
			index ++;
		}
	}
	



	int m,l,r;
	for(int i = 1;i<=k;i++)
	{
		scanf("%d %d %d",&m,&l,&r);
		printf("Case #%d:\n",i);
		int P=0;
		for(int j = 0;j<index && P<m;j++ )
		{
			if(sum[j].age <=r && sum[j].age >=l)
			{
				
				printf("%s %d %d\n",sum[j].name,sum[j].age,sum[j].worth);
				P++;
			}
		}
		if(P==0)
			printf("None\n");
	}
	
	
	return 0;
} 
在这里插入代码片

猜你喜欢

转载自blog.csdn.net/qq_15556537/article/details/88892158