整数拆分(动态规划)

1.将正整数n无序拆分成最大数为m的拆分方案个数,要求所有拆分方案不重复。

样例:

n = 5, m = 5,对应的拆分方案如下:

5 = 5

5 = 4 + 1

5 = 3 + 2

5 = 3 + 1 + 1

5 = 2 + 2 + 1

5 = 2 + 1 + 1 + 1

5 = 1 + 1 + 1 + 1 + 1

分析:

(1)当n=1,无论m为多少,只有{1}一种划分

(2)当m=1,无论n为多少,只有{1,1,1…}一种划分

(3)当n<m,f(n,m)=f(n,n)

(4)当n=m,如果划分中有n,则只有{n}一种划分;当划分中没有n,则f(n,n)=f(n,n-1)

f(n,n)= 1 + f(n,n - 1)

(5)当n>m,如果划分中有m,则{m,{x1,x2,…} = n - m},f(n,m)=f(n - m, m);当划分中没有m,f(n,m)=f(n,m - 1)

f(n,m) = f(n - m, m)+ f(n,m - 1)

import java.util.Scanner;

public class Main {
	
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner scanner = new Scanner(System.in);
		while (scanner.hasNext()){
			int n = scanner.nextInt();
			int m = scanner.nextInt();
			int temp = integerhuafen(n, m);
			System.out.print(temp);
		}		
	}
	public static int integerhuafen(int n, int m) {
		
		int dp[][] = new int[n + 1][m + 1];		
		for(int i = 1; i <= n; i++){
			for(int j = 1; j <= m; j++ ){
				if(i == 1 || j == 1){
					dp[i][j] = 1;
				}else if (i == j) {
					dp[i][j] = 1 + dp[i][j - 1];
				}else if (i < j) {
					dp[i][j] = dp[i][i];
				}else {
					dp[i][j] = dp[i - j][j] + dp[i][j - 1];
				}
			}
		}
		return dp[n][m];		
	}
}

  

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转载自www.cnblogs.com/smilexuezi/p/11553105.html