Given three integers A, B and C in [-2^63^, 2^63^], you are supposedto tell whether A+B > C.
Input Specification:
The first line of the input gives the positive number of test cases, T(<=10). Then T test cases follow, each consists of a single linecontaining three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line "Case #X: true" if A+B>C, or"Case #X: false" otherwise, where X is the case number (starting from1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
#include<cstdio> //不要以为直接加就行了。。。还要考虑溢出的情况 int main() { int T, i = 1; scanf("%d", &T); while (T--) { long long a, b, c; scanf("%lld %lld %lld", &a, &b, &c); bool flag; long long res = a + b; if (a < 0 && b < 0 && res>=0) flag = false; //这两个判断条件是计算机组成的知识。。。自己去推吧。。 else if (a > 0 && b > 0 && res< 0)flag = true; else if (res > c) flag = true; //a+b必须存放到long long型变量中,再去比较;直接比较会出错(我也不知道为啥。) else flag = false; if (flag == true) printf("Case #%d: true\n", i++); else printf("Case #%d: false\n", i++); } return 0; }