版权声明:get busy living...or get busy dying https://blog.csdn.net/qq_41444888/article/details/89389525
https://vjudge.net/problem/POJ-1182
当个带权并查集模板吧,解决问题的关键在于在向量之间确立联系,并且保证这种联系符合向量运算法则
#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<vector>
#include<set>
#include<map>
#include<queue>
#include<cmath>
#define ll long long
#define mod 1000000007
#define inf 0x3f3f3f3f
using namespace std;
const int maxn = 50005;
int pre[maxn], val[maxn];
int find(int x)
{
if(pre[x] != x)
{
int tmp = pre[x];
pre[x] = find(pre[x]);
val[x] = (val[x] + val[tmp]) % 3;
}
return pre[x];
}
int main()
{
int n, m;
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i ++)
{
pre[i] = i;
val[i] = 0;
}
int u, v, w;
int ans = 0;
for(int i = 1; i <= m; i ++)
{
scanf("%d%d%d", &w, &u, &v);
if(u > n || v > n || (w == 2 && u == v))
ans ++;
else
{
int fu = find(u), fv = find(v);
if(fu == fv)
{
if((w - 1) != ((val[u] - val[v] + 3) % 3))
ans ++;
}
else
{
pre[fu] = fv;
val[fu] = (w - 1 + val[v] - val[u]) % 3;
}
}
}
printf("%d\n", ans);
return 0;
}